desmond00766
desmond00766 desmond00766
  • 07-11-2021
  • Mathematics
contestada

If k + 1, 2k - 1 and 3k + 1 are three consecutive terms of a GP, find the value of the common ratio​

Respuesta :

mathstudent55
mathstudent55 mathstudent55
  • 07-11-2021

Answer:

r = -1 or r = 5/3

Step-by-step explanation:

(2k - 1)/(k + 1) = (3k + 1)/(2k - 1)

(2k - 1)^2 = (k + 1)(3k + 1)

4k^2 - 4k + 1 = 3k^2 + 4k + 1

k^2 - 8k = 0

k(k - 8) = 0

k = 0 or k = 8

For k = 0,

(2k - 1)/(k + 1) = -1/1 = 1

For k = 8,

(2k - 1)/(k + 1) = 15/9 = 5/3

Answer Link

Otras preguntas

how can 5 people equally share a 3 segment gummy worm
Right 247.903 in expanded form
Twice a number (x) is less than 10.
Is blood an element or compound?
What geographic factors account for the diversity of cultures in the Himalayas?
What number between 0 and 20 has five factors
What was the Renaissance? a. a period--during the thirteenth century--of renewed interest in ancient civilizations in Europe b. a period of artistic and litera
which amendment banned alcohol
What was the Renaissance? a. a period--during the thirteenth century--of renewed interest in ancient civilizations in Europe b. a period of artistic and litera
Which is bigger 3/7 or 2/5