ushagrg52 ushagrg52
  • 09-10-2021
  • Physics
contestada

two vectors a is 3i-4j-5k and 6i+2j-5k find angle between a and b

Respuesta :

Adrax
Adrax Adrax
  • 09-10-2021

Answer:

check the image for the solution in steps

Ver imagen Adrax
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Answer Link
bamboola1 bamboola1
  • 09-10-2021

Answer:

COS  7.51

Explanation:

3i-4j-5k  + 6i+2j-5k

now,

= (3i - 4j + 5k).(6i + 2j - 5k)

= (3.6 - 4.6 + 5.-5)

= (18 - 24 - 25)

= -31

Magnitude of A is  SQRT 3^2 - 4^2 - 5^2 =  SQRT  9 -16-25 = SQ -32

Magnitude of B IS SQRT 6^2+2^2-5^2 = SQRT 36+4-25 = SQRT 15

COS THETA = -31 / SQ RT -32+15  = -31/ SQ RT 17 = -7.51860438

COS THETA = COS  7.51

Answer Link

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