Answer:
6x+16
Step-by-step explanation:
[tex]\frac{d}{dx} [(x+5)(3x+1)]\\=\frac{d}{dx} [x+5]*(3x+1)+(x+5)*\frac{d}{dx} [3x+1]\\=(\frac{d}{dx} [x]+\frac{d}{dx} [5])(3x+1)+(x+5)(3*\frac{d}{dx} [x]+\frac{d}{dx} [1])\\=(1+0)(3x+1)+(x+5)(3*1+0)\\=3(x+5)+3x+1\\Simplify/Rewrite\\=6x+16[/tex]
