Respuesta :

Answer:

x=16

y=23°

z=16

Step-by-step explanation:

we assume it is a kite.

[tex]NM=\sqrt{NQ^2+MQ^2} \\z=\sqrt{8^2+6^2} =\sqrt{64+36} =\sqrt{100} =10[/tex]

∠NQM=90°

4y-2=90

4y=90+2=92

y=92/4=23°·

NP=2Nq

x=2×8=16