[tex]\boxed{\sf \dfrac{d}{dx}x^n=nx^{n-1}}[/tex]
[tex]\boxed{\sf \dfrac{d}{dx}sinx=cosx}[/tex]
Now
[tex]\\ \sf\longmapsto \dfrac{d}{dx}(x+1)sinx[/tex]
[tex]\\ \sf\longmapsto 1+cosx[/tex]
sin x + x · cos x + cos x
Step-by-step explanation:
f(x) = u · v → f'(x) = u' · v + u · v'
f(x) = (x + 1) sin x
f'(x) = 1 · sin x + (x + 1) · cos x
f'(x) = sin x + x · cos x + cos x
