Answer:
yes, point T lies on the perpendicular bisector of NP
Step-by-step explanation:
M (x,y) : midpoint of NP
x = (5+1)/2 = 3 y = (7+1)/2 = 4
M (3,4)
slope TM (m'): (4-2) / (3-6) = - 2/3
slope of NP (m): (7-1) / (5-1) = 6/4 = 3/2
m' = - 1/m
TM ⊥ NP
