Explanation:
i1=1ampere
i1+i2=I
VA−VB=i1×3Ω=i2×6
⇒1×3=i2×6
2i=21ampere
Hence I=i1+i2=1+0.5=1.5ampere
Req=2+3+63×6=2+93×6=4Ω
equivalent circuit
Refer image .2
From KVL
1req=v
v=1.5×4
