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09-09-2021
Mathematics

contestada

evaluate: sigma 20 and 1 = (3n+2)
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Respuesta :

09-09-2021

Answer:

Step-by-step explanation:

[tex]\displaystyle \sum_{n=1}^{20} (3n+2)=\dfrac{(62+5)*20}{2} =10*67=670\\[/tex]

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