Find f(x)+g(x), given f(x)=x^2-8 and g(x)=-2-x^2


The ^means there’s a 2 over top of that number please show your steps if you solve this for me

Respuesta :

[tex]\left(x^2-8\right)+\left(-2-x^2\right)=-10[/tex]

[tex]\left(x^2-8\right)+\left(-2-x^2\right)[/tex]

[tex]=x^2-8-2-x^2[/tex]

[tex]=x^2-x^2-8-2[/tex]

[tex]=-8-2[/tex]

[tex]=-10[/tex]