Answer:
Step-by-step explanation:
It doesn't matter what order they are chosen in, so the numerator is 64C3.
The total number of ways that you can choose any 3 crayons is 64 * 63 * 62
P(r and y and b) = 64! / (62! 3!) // 64 * 63 * 62
P(r and y and b) = 64 * 63 * 62 / 6 // 64 * 63 * 62 = 41664 / 249984 = 0.167
