Answer:
√x⁸y² of question 3
= x⁸/² y²/²
=x⁴y
[tex] \sqrt{2} (6 + \sqrt{12} ) = 6 \sqrt{2} + 2 \sqrt{6} [/tex]
[tex] \sqrt{ {x}^{8} {y}^{2} } = {x}^{4} y[/tex]
[tex] \sqrt{8} \sqrt{18} = 12[/tex]
I hope I helped you^_^
