[tex]\huge\mathsf\green{ANSWER}:—[/tex]
[tex]option \: c \: \sqrt{4} \: is \: the \: correct \: option[/tex]
[tex] \sqrt{4} = \sqrt{2 \times 2} = 2[/tex]
But irrational numbers are the numbers that are not rational numbers but 2 is a rational number that's why option c is correct .
