Answer:
First, we substitute k=-2 in the given expression and we calculate the numerical value.
[tex]\frac{5(2k-3)-3(k+4}{3k+2} =\frac{512(-2)-3](-2+4}{3(-2)+2}[/tex]
[tex]=\frac{5(-4-3)-3(2)}{-6+2}[/tex]
[tex]=\frac{5(-7)-6}{-4}[/tex]
[tex]=\frac{-41}{-4}[/tex]
[tex]=\frac{41}{4}[/tex]
OAmalOHopeO
Answer:
-33
Step-by-step explanation:
5(2k - 3 )-3(k+4)/ 3k+2
5(2*(-2)-3)-3((-2)+4)/3*(-2)+2
5(-4-3)-3(2)/(-6)+2
5(-7)-6/(-6)+2
-35+1+2
-33
