Answer:
0.804% to 3 dec places.
Step-by-step explanation:
If the first 4 throws are a dot and the next 2 are not:
Probability = (1/6)^4 * (5/6)^2
= 25/46656
There are 6C4 ways for this to happen
6C4 = (6*5*4*3)/ (4*3*2*1) = 15 ways.
So The required probability = (25*15)/46656
= 125/15552
= 0.00804
= 0.804%
