Respuesta :

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Hi there!

[tex]\large\boxed{\text{ B. 2}}[/tex]

f(x) = 2x + 6

Differentiating 2x = 2 (Power rule, dy/dx xⁿ =  nxⁿ⁻¹)

Differentiating a constant always equals 0.

Thus:

f'(x) = 2

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