MyDDesiLonlilook
MyDDesiLonlilook MyDDesiLonlilook
  • 10-12-2016
  • Physics
contestada

If a 375 mL sample of water was cooled from 37.5 C to 0 C how much heat was lost in joules?

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Аноним Аноним
  • 15-12-2016
please, you have to apply the formula below:

Q=c∗m∗Δt

where Q is the energy lost,
 
c is the specific heat of water,
 
m is the mass of water involved,

so m=3.75 *10^-1 Kg
 
c=4,184 J/(Kg*°C)

delta t=37.5 °C

I hope my answer has come to your help. God bless and have a nice day ahead!
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