Respuesta :

Answer:

[tex]let \: the \: inverse \: be \: m \\ m = \frac{1}{x - 12} \\ m(x - 12) = 1 \\ mx - 12m = 1 \\ x = \frac{1 + 12m}{m} \\ \therefore \: f {}^{ - } (x) = h(x) = \frac{1 + 12x}{ x} [/tex]