Answer:
3rd option
Step-by-step explanation:
([tex]\frac{f}{g}[/tex] )(x)
= [tex]\frac{f(x)}{g(x)}[/tex]
= [tex]\frac{2x^2-5x-3}{2x^2+5x+2}[/tex] ← factorise numerator and denominator
= [tex]\frac{(x-3)(2x+1)}{(x+2)(2x+1)}[/tex] ← cancel (2x + 1) on numerator/ denominator
= [tex]\frac{x-3}{x+2}[/tex]
