Answer:
AB is shortest side
Step-by-step explanation:
According to given question circuit represented as,
From the images
[tex]cos 30^0=\frac{BC}{38} \\0.86=\frac{BC}{38} \\BC=32.68 cm[/tex]
Now,
[tex]sin 30^0=\frac{AB}{38} \\0.5=\frac{AB}{38} \\AB=19 cm[/tex]
Therefore, AB is shortest side
