jaichandraprasad17
jaichandraprasad17 jaichandraprasad17
  • 09-06-2021
  • Mathematics
contestada

show that 21^n, n €N can never ends with 0,2,4,6 and 8​

Respuesta :

sreedevi102
sreedevi102 sreedevi102
  • 09-06-2021

Answer:

Step-by-step explanation:

[tex]21 ^n = (3 \times 7)^n[/tex]

21 has no 2 in it's prime factorization. So it can never end in 0, 2 , 4 , 6 , 8.

 OR

Odd number raise to any number is always odd, Which does not include 2, 4, 6 , 8.

So [tex]21^n[/tex] does not end with 0, 2, 4 , 6 , 8.

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