Answer:
[tex]\cos(J) = 0.67[/tex]
Step-by-step explanation:
Given
[tex]\angle K = 90^o[/tex]
[tex]KJ = 65[/tex]
[tex]IK = 72[/tex]
[tex]JI = 97[/tex]
Required
[tex]\cos(J)[/tex]
The question is illustrated with the attached image.
From the image, we have:
[tex]\cos(J) = \frac{KJ}{JI}[/tex]
This gives:
[tex]\cos(J) = \frac{65}{97}[/tex]
[tex]\cos(J) = 0.67010309278[/tex]
[tex]\cos(J) = 0.67[/tex] --- approximated
