Respuesta :

sreedevi102

Answer:

option A

Step-by-step explanation:

[tex]\frac{x^a}{x^b} = x^{a-b}[/tex] , [tex]z^0 = 1[/tex]

So,

[tex]\frac{18x^5 y}{6xy^8z^0} = \frac{18}{6} \times x^{5 -1} \times y^{1-8} = 3 x^4 \times y^{-7} = \frac{3x^4}{y^7}[/tex]