The value for the constant, d which makes x= -1 an extraneous solution is; d=5.
Which value for the constant d makes x=-1 an extraneous solution in the equation?
The constant d as given in the task content can be evaluated as follows where, x =-1;
√(8+1) + = 2(-1) +d
√9 = -2 +d
3 = -2 +d.
d = 5.
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