Answer:
let total be U and strawberry be S and.apple be A .
now
n[U]=200
n[S]=56% 0f 200=112
n[A]=44%of 200=88
n[A n S]=30%of 200=60
now
[tex] \bar {A U S}=?[/tex]
we have
n[U]=n[A] +n[B]-n[ A n B]+[tex] \bar{A U S}[/tex]
[tex] \bar{A U S}[/tex]=200-112-88+60=60
option C. 60 is a required answer.
