Answer:
-5+(√x-3) and -(√x-3)-5
Step-by-step explanation:
change f(x) to 'y' and then interchange x and y; then solve for y
y = x² + 10x + 28
x = y² + 10y + 28
you can use the Quadratic Formula to evaluate y² + 10y + 28 and will get:
-5+(√x-3) and -(√x-3)-5
