Answer:
[tex]1 + cot^2 \theta[/tex]
Step-by-step explanation:
Given the expression;
[tex]\frac{tan^2\theta+1}{tan^2 \theta}[/tex]
Separating into partial fraction;
[tex]\frac{tan^2 \theta}{tan^2 \theta} + \frac{1}{tan^2 \theta}\\= 1 + \frac{1}{tan^2 \theta}\\\\[/tex]
Since [tex]\frac{1}{tan \theta} = cot \theta\\[/tex]
Hence the expression becomes;
[tex]1 + cot^2 \theta[/tex]
