Answer:
[tex]x = 3\ or\ x = 7[/tex]
Step-by-step explanation:
Given
[tex]x^{2}-8x+14=2x-7[/tex]
Required
Solve
Equate to 0
[tex]x^{2}-8x-2x+14+7=0[/tex]
[tex]x^{2}-10x+21=0[/tex]
Expand
[tex]x^{2}-7x-3x+21=0[/tex]
Factorize
[tex]x(x-7)-3(x-7)=0[/tex]
Factor out x - 7
[tex](x-3)(x-7)=0[/tex]
Split
[tex]x - 3 = 0\ \ x - 7 = 0[/tex]
Solve
[tex]x = 3\ or\ x = 7[/tex]
