Answer:
W = 20 J
Explanation:
Given that,
Charge, q = 2 C
It is moves from a point at 118 volt to a point at 128 volt.
We need to find the work done in moving the charge,
[tex]W=\Delta VQ[/tex]
Put all the values,
[tex]W=(128-118)\times 2\\\\W=20\ J[/tex]
So, the work done in moving the charge is 20 J.
