Answer:
36π [tex]in^{3}[/tex]
Step-by-step explanation:
A = [tex]\pi r^{2}[/tex] = 9π
[tex]r^{2} = 9[/tex]
r = 3 = radius of the sphere
V = [tex]\frac{4\pi r^{3} }{3}[/tex] = [tex]\frac{4\pi 3^{3} }{3} = \frac{4\pi *27}{3}[/tex]
= 36π [tex]in^{3}[/tex]
