Respuesta :

msm555

Answer:

Solution given:

  • (sinx+cosx)^2-(sinx-cosx)^2
  • sin²x+2sinxcosx+cos²x-(sin²x-2sinxcosx+cos²)
  • 1+2sinxcosx-1+2sinxcosx
  • 2(2sinxcosx)
  • 2sin2x

Step-by-step explanation:

[note: sin²x+cos²x=1]

Answer:

(sinx+coax+sinx-cosx) ( sinx+cosx-sinx+cosx)

4sinxcosx

2sin2x