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08-05-2021
Chemistry

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5L of air at-50 C is warmed to 100 C. What is the new volume?

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Trancescient Trancescient

08-05-2021

Answer:

V2 = 5.8 L

Explanation:

T1 = 50°C = 323 K

V1 = 5L

T2 = 100°C = 373 K

V2 =?

According to Charles's law,

V1/T1 = V2/T2

---> V2 = (T2/T1)V1 = (373K/323K)(5 L)

= 5.8 L

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