The molarity of a solution that contains 28 g KOH (molar mass 56 g/mol) per 250 mL of solution is:

Question

08-04-2021
Chemistry

contestada

The molarity of a solution that contains 28 g KOH (molar mass 56 g/mol) per 250 mL of solution is:

Respuesta :

Otras preguntas

Refer to Explorations in Literature for a complete version of this narrative. Which statement best describes the narrator's reliability in "The Black Cat"?

Which of the experiences that equiano described would be hardest for you to endure? explain why?

If there is a loss of 4.36 × 10-5 g of mass in a nuclear reaction, how many kJ of energy would be released? Recall that c = 3 × 108 m/s.

What can be inferred from the following lines from the play Everyman? Beauty, Strength, and Discretion do man forsake, Foolish friends and kinsmen, that fair sp

Let statements...... When 10 is subtracted from the quotient of a number and four, the difference is two. What is the number?

3O2(g) 2O3(g); Keq = 1 Which equation compares the concentration of oxygen and ozone? [O2]3 = [O3]2 [O2] = [O3] [O2] = [O3]3/2 [O2]2 = [O3]3

The word fancy most nearly means

sally has 10.00 worth of coins and all of the coins are equal how many coins of each does she have?

What body of water is connected to the panama canal zone?

dvnl dvnl · Answer 1 · 2021-04-09T00:02:43+02:00

dvnl dvnl

09-04-2021

Molarity = moles of solute/volume of solution in liters

The solute here is KOH. We have the mass of KOH, and we can calculate the number of moles by dividing by the molar mass: (28 g KOH)/(56 g/mol) = 0.5 mol KOH. The volume of our solution is 0.250 L.

So, the molarity of the solution would be (0.5 mol KOH)/(0.250 L) = 2 mol/L KOH or 2 M KOH.

Answer Link