myraclehenson92
myraclehenson92 myraclehenson92
  • 08-04-2021
  • Mathematics
contestada

please helpppp meeeeee

please helpppp meeeeee class=

Respuesta :

elsiewilliams56e elsiewilliams56e
  • 08-04-2021

Step-by-step explanation

tan∞20° = BC÷ BA = 3 ÷ BA

tan∞20°°= 3÷ BA

÷ by BA

⇒Tan∞20°BA= 3

÷ BY tan∞20°

tan∞20°BA÷tan20°BA= 3÷tan∞20°BA

BA= 3÷TAN∞20°BA

BA= 8.24

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