9514 1404 393
Answer:
B. -1
Step-by-step explanation:
[tex]\dfrac{x^2 +5x +6}{x+3}=1\qquad\text{given}\\\\\dfrac{(x+2)(x+3)}{x+3}=1\qquad\text{factor}\\\\x+2=1\qquad x\ne-3\qquad\text{cancel factors}\\\\x=-1\qquad\text{add $-2$}[/tex]
The only valid value of x is -1.
