The tangent line to f(x) = e ˣ at the point x = 2 has slope equal to f ' (2):
f(x) = e ˣ → f '(x) = e ˣ → f ' (2) = e ²
At x = 2, the function takes on a value of f (2) = e ². Use the point-slope formula to get the equation of the tangent line:
y - e ² = e ² (x - 2)
Solve for y :
y = e ² x - e ²
