Answer:
Cu⁺² is being reduced in that reaction.
Explanation:
- Zn(s) + Cu⁺²(aq) → Zn⁺²(aq) + Cu(s)
When a substance is reduced, its oxidation number is reduced -changing to a lower value than original-.
Cu⁺² turned into Cu. Meaning that the oxidation number changed from +2 to 0.
Thus, Cu⁺² is being reduced in that reaction.
