Answer:
B, [tex]8\sqrt{2}[/tex]
Step-by-step explanation:
Diagonals of a square are congruent so AC= 4
using pythagorean theorem we can then do [tex]x^{2} +x^{2}[/tex]=[tex]4^{2}[/tex]
[tex]2x^{2} = 16\\x^{2} =8\\x=\sqrt{8} \\x=2\sqrt{2}[/tex]
Then for perimeter we times the [tex]2\sqrt{2}[/tex] by 4 and get
[tex]8\sqrt{2}[/tex]
Hope this helps and please mark brainliest!!
