Answer:
(x-3)²+(y+5)²=16
Step-by-step explanation:
[tex] \large \boxed{ {(x - h)}^{2} + {(y - k)}^{2} = {r}^{2} }[/tex]
The equation above is an equation of circle with a centre at (h,k) and has radius = r
Substitute h = 3, k = -5 and r = 4 in the equation.
[tex] \large{ {(x - 3)}^{2} + {(y - ( - 5))}^{2} = {4}^{2} } \\ \large{ {(x - 3)}^{2} + {(y + 5)}^{2} = 16}[/tex]
