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  • 10-03-2021
  • Mathematics
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Help!!!!!!!!!find the equation of the linear function q(16)=1 that is parralel to f(x)=1/3x+39


It wants it in slope intercept form

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s1802468 s1802468
  • 10-03-2021

Answer:

[tex]q(x)= \frac{1}{3} x -\frac{13}{3}[/tex]

Step-by-step explanation:

So you have (16, 1)

When two linear functions are parallel, they have the same slope.

So function q also has a slope of 1/3x. You have a set of points so you can plug them in a slope intercept equation to find b.

y= mx+b

m= slope

y= y-intercept

1= 1/3(16) +b

1 - (16/3) = b

b= -13/3

so then, [tex]y= \frac{1}{3} x -\frac{13}{3}[/tex]

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