Answer:
V₂ = 50.93 L
Explanation:
Initial volume, [tex]V_1=43.1\ L[/tex]
Initial temperature, [tex]T_1=24^{\circ} C=24+273=297\ K[/tex]
Final temperature, [tex]T_2=78^{\circ} C=78+273=351\ K[/tex]
We need to find the final volume of the gas. The relation between the volume and the temperature is given by :
[tex]\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}\\\\V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{43.1\times 351}{297}\\\\V_2=50.93\ L[/tex]
So, the final volume of the gas is 50.93 L.
