adeeb7269 adeeb7269

10-03-2021
Chemistry

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What is the work when a gas expands from 0.666 L to 2.334 L against an external pressure of 2.07 atm?

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drpelezo drpelezo

10-03-2021

Answer:

work = 3.45 Joules

Explanation:

Work from the 1st Law of Thermodynamics is PΔV in the equation of internal energy => ΔE = ΔH + PΔV.

Therefore, work = PΔV = 2.07atm·(2.334L - 0.666L) = 3.45 L·atm = 3.45 Joules

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