Can you help me, please? Thank you.
Answer:
[tex]\frac{-4+6}{2} , \frac{3+2}{2} =1,4\\\\\frac{6+6}{2} ,\frac{5+(-1)}{2} =6,2\\\\\frac{-4+6}{2} ,\frac{3+(-1)}{2} =1,1[/tex]
Step-by-step explanation:
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