A rock is thrown downward with velocity 10 ft/sec from a
bridge 100 ft above the water. The velocity of the rock upon impact on the
water can be solve using the formula:
V= sqroot(2gy) where g is the acceleration due to gravity
and y the height
V= sqroot(2 (32.2 ft/s2) (100ft) = 80.25 ft/s
