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A 480-kg car moving at 14.4 m/s hits from behind a 570-kg car moving at 13.3 m/s in the same direction. If the new speed of the heavier car is 14.0 m/s, what is the speed of the lighter car after the collision, assuming that any unbalanced forces on the system are negligibly small?

This question involves the conservation of momentum. The system under consideration will be the two cars.
Total momentum before collision = total momentum after collision
momentum = mass x velocity
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
480 x 14.4 + 570 x 13.3 = 480v₁ + 570 x 14
v₁ = 13.6 m/s

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I need help A 480-kg car moving at 14.4 m/s hits from behind a 570-kg car moving at 13.3 m/s in the same direction. If the new speed of the heavier car is 14.0 m/s, what is the speed of the lighter car after the collision, assuming that any unbalanced forces on the system are negligibly small?

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I need help
A 480-kg car moving at 14.4 m/s hits from behind a 570-kg car moving at 13.3 m/s in the same direction. If the new speed of the heavier car is 14.0 m/s, what is the speed of the lighter car after the collision, assuming that any unbalanced forces on the system are negligibly small?