Answer:
[tex]25C_{12}[/tex]
Step-by-step explanation:
We are given that an expression
[tex]\frac{25!}{(25-12)!12!}[/tex]
We have to find the expression which represents [tex]\frac{25!}{(25-12)!12!}[/tex].
We know that
[tex]nP_r=\frac{n!}{(n-r)!}[/tex]
[tex]nC_r=\frac{n!}{(n-r)!r!}[/tex]
By using the formula
By comparing we get
n=25,r=12
[tex]\frac{25!}{(25-12)!12!}[/tex]
[tex]=25C_{12}[/tex]
Hence, option a is true.
[tex]25C_{12}[/tex]
