Answer:
- [tex]\frac{5x}{7}[/tex]
Step-by-step explanation:
Given
[tex]\frac{5x-10x^2}{14x-7}[/tex] ← factor out 5x in the numerator and 7 in the denominator
= [tex]\frac{5x(1-2x)}{7(2x-1)}[/tex] ← factor out - 1 on the numerator
= [tex]\frac{-5x(2x-1)}{7(2x-1)}[/tex] ← cancel the common factor (2x - 1)
= - [tex]\frac{5x}{7}[/tex]
