The volume occupied by 100g of oxygen gas at STP is 70L.
1 mole of a gas at STP occupies 22.4 L volume.
The same goes for oxygen gas, [tex]O_2[/tex]. 1 mole of [tex]O_2[/tex] occupies 22.4L volume.
Now the molar mass of [tex]O_2[/tex] is = 32g
So the number of moles of [tex]O_2[/tex] in 100g is
n = 100/32
n = 3.125 moles
Volume occupied by 3.125 moles or 100g of [tex]O_2[/tex] is
V = 3.125 × 22.4 L
V = 70 L volume is occupied by 100g of oxygen gas.
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