Answer:
[tex]Q_{vap}=7.90x10^5J[/tex]
Explanation:
Hello!
In this case, since this is the vaporization process of water, we need to keep in mind that the enthalpy of vaporization of this compound is 2.256 kJ/g, for 350 g, we obtain:
[tex]Q_{vap}=m*\Delta H_{vap}\\\\Q_{vap}=350g*2.256\frac{kJ}{g} *\frac{1000J}{1kJ} \\\\Q_{vap}=7.90x10^5J[/tex]
Because the process is carried out at 100 °C, the boiling temperature of water, already.
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