Subtract sin (8x − 10) from both sides of the equation.
cos (6x − 12) − sin (8x − 10) = 0
Answer:
It doesn't exist
Step-by-step explanation:
since :
cos (90° – x) = sin x
cos(x) = sin(pi/2 - x)
then
cos(6x-12) =! sin(8x-10)
since (8x-10) =! (pi/2- 6+12)
then this identity of cos(6x-12) = sin(8x-10) doesn't exist
