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Consider the line y = 6x-7. Find the equation of the line that is perpendicular to this line and passes through the point (8, 3). Find the equation of the line that is parallel to this line and passes through the point (8, 3).

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osaedennis23 osaedennis23 · Answer 1 · 2021-01-10T09:20:21+01:00

Answer:

y = (-x + 8)/6

Step-by-step explanation:

y =6x-7

gradient of perpendicular to the line above is -1/6.

using the point (8,3)

y - y1 = m(x - x1)

y - 3 = -1/6(x - 8)

6y-18 = -1(x - 8)

y = (-x + 26)/6

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